Algebra 1 · Systems of equations

How to Solve a System of Equations by Elimination

Problem

2x+3y=12,x−y=12x + 3y = 12,\quad x - y = 1

Answer

x=3, y=2x = 3,\ y = 2

Elimination removes one variable by adding two equations. Make the coefficients of one variable opposites, add, then solve the equation that is left.

Step-by-step solution

  1. Pick a variable and make its coefficients opposites.

    3(x−y)=3(1)⇒3x−3y=33(x - y) = 3(1) \Rightarrow 3x - 3y = 3

    Why: Multiplying the second equation by 3 turns -y into -3y, which is the opposite of +3y in the first equation.

  2. Add the two equations.

    (2x+3y)+(3x−3y)=12+3(2x + 3y) + (3x - 3y) = 12 + 3

    Why: The y terms cancel, leaving one equation in x.

  3. Solve for x.

    5x=15⇒x=35x = 15 \Rightarrow x = 3

    Why: Divide both sides by 5.

  4. Substitute x = 3 into an original equation.

    3−y=1⇒y=23 - y = 1 \Rightarrow y = 2

    Why: The solution needs both values, and the simpler equation gives y quickly.

Common mistakes

  • Multiplying only the left side of x - y = 1 by 3. The right side must be multiplied too.
  • Adding when the coefficients are the same sign. Add only when the coefficients are opposites.
  • Stopping after finding x. Write the pair (3, 2).

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. x+y=7, x−y=3x + y = 7,\ x - y = 3

    Show answer

    x=5, y=2x = 5,\ y = 2

  2. 2x+y=9, x−y=32x + y = 9,\ x - y = 3

    Show answer

    x=4, y=1x = 4,\ y = 1

  3. 3x+2y=12, x−2y=43x + 2y = 12,\ x - 2y = 4

    Show answer

    x=4, y=0x = 4,\ y = 0

  4. x+3y=10, x−y=2x + 3y = 10,\ x - y = 2

    Show answer

    x=4, y=2x = 4,\ y = 2

  5. 2x+5y=20, 2x−y=82x + 5y = 20,\ 2x - y = 8

    Show answer

    x=5, y=2x = 5,\ y = 2