Algebra 1 · Systems of equations

How to Solve a System of Equations by Substitution

Problem

y=2x+1,3x+y=11y = 2x + 1,\quad 3x + y = 11

Answer

x=2, y=5x = 2,\ y = 5

Substitution works well when one equation already gives a variable by itself. Replace that variable in the other equation, solve, then find the second value.

Step-by-step solution

  1. Substitute 2x + 1 for y in the second equation.

    3x+(2x+1)=113x + (2x + 1) = 11

    Why: Both equations describe the same y, so the expressions are equal.

  2. Combine like terms.

    5x+1=115x + 1 = 11

    Why: 3x plus 2x is 5x.

  3. Subtract 1 from both sides.

    5x=105x = 10

    Why: Subtracting undoes the addition.

  4. Divide both sides by 5.

    x=2x = 2

    Why: Dividing by the coefficient leaves x alone.

  5. Substitute x = 2 into the first equation to find y.

    y=2(2)+1=5y = 2(2) + 1 = 5

    Why: The solution needs both values.

Common mistakes

  • Substituting into the same equation. Use the other equation.
  • Dropping the parentheses around 2x + 1.
  • Stopping after finding x. The solution is the pair (2, 5).

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. y=x+2, x+y=8y = x + 2,\ x + y = 8

    Show answer

    x=3, y=5x = 3,\ y = 5

  2. y=2x, x+y=9y = 2x,\ x + y = 9

    Show answer

    x=3, y=6x = 3,\ y = 6

  3. y=x−1, 4x+y=14y = x - 1,\ 4x + y = 14

    Show answer

    x=3, y=2x = 3,\ y = 2

  4. y=2x−3, x+y=9y = 2x - 3,\ x + y = 9

    Show answer

    x=4, y=5x = 4,\ y = 5

  5. y=5x, 2x+y=21y = 5x,\ 2x + y = 21

    Show answer

    x=3, y=15x = 3,\ y = 15