Algebra 1 · Systems of equations

Solve a System by Elimination with Multiplication

Problem

4x+3y=18,2x−y=44x + 3y = 18,\quad 2x - y = 4

Answer

x=3, y=2x = 3,\ y = 2

When elimination needs a multiplier, pick the variable with the simplest coefficients. Multiply one equation, make the coefficients opposites, then add.

Step-by-step solution

  1. Choose the variable to eliminate.

    eliminate y\text{eliminate } y

    Why: The y coefficients are +3 and -1, so one multiplication can line them up.

  2. Multiply the second equation by 3.

    3(2x−y)=3(4)⇒6x−3y=123(2x - y) = 3(4) \Rightarrow 6x - 3y = 12

    Why: This turns -y into -3y, the opposite of +3y.

  3. Add the equations to cancel y.

    (4x+3y)+(6x−3y)=18+12(4x + 3y) + (6x - 3y) = 18 + 12

    Why: The y terms add to zero.

  4. Solve for x.

    10x=30⇒x=310x = 30 \Rightarrow x = 3

    Why: Divide both sides by 10.

  5. Substitute x = 3 into 2x - y = 4.

    6−y=4⇒y=26 - y = 4 \Rightarrow y = 2

    Why: The second original equation is the quickest place to find y.

Common mistakes

  • Multiplying only the x term by 3. Every term and the right side must be multiplied.
  • Adding before the coefficients are opposites, so nothing cancels.
  • Substituting x = 3 into the multiplied equation and then forgetting to check it in both originals.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. 3x+2y=16, x−y=23x + 2y = 16,\ x - y = 2

    Show answer

    x=4, y=2x = 4,\ y = 2

  2. 2x+3y=13, x+y=52x + 3y = 13,\ x + y = 5

    Show answer

    x=2, y=3x = 2,\ y = 3

  3. 5x+2y=19, x−y=15x + 2y = 19,\ x - y = 1

    Show answer

    x=3, y=2x = 3,\ y = 2

  4. 3x+4y=18, x+y=53x + 4y = 18,\ x + y = 5

    Show answer

    x=2, y=3x = 2,\ y = 3

  5. 4x+y=11, x−2y=54x + y = 11,\ x - 2y = 5

    Show answer

    x=3, y=−1x = 3,\ y = -1