Trigonometry · Sine and cosine graphs

How to Find the Period of a Sine Function

Problem

y=sin⁡(3x)y = \sin(3x)

Answer

2π3\frac{2\pi}{3}

Sine and cosine repeat forever. The period is the length of one full repeat, and b controls how fast the wave cycles.

Step-by-step solution

  1. Match the function to the form y = sin(bx).

    b=3b = 3

    Why: The number in front of x is b.

  2. Write the period formula.

    T=2πbT = \frac{2\pi}{b}

    Why: The period is one full repeat of the wave.

  3. Substitute b and simplify.

    T=2π3T = \frac{2\pi}{3}

    Why: A larger b makes the wave repeat faster and the period shorter.

Common mistakes

  • Reading the period as 3. The b value scales the period, it is not the period.
  • Using pi instead of 2pi. One full turn is 2pi.
  • Taking b from the whole expression, such as 3x.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. y=sin⁡(2x)y = \sin(2x)

    Show answer

    π\pi

  2. y=sin⁡(4x)y = \sin(4x)

    Show answer

    π2\frac{\pi}{2}

  3. y=sin⁡(x2)y = \sin\left(\frac{x}{2}\right)

    Show answer

    4π4\pi

  4. y=sin⁡(5x)y = \sin(5x)

    Show answer

    2π5\frac{2\pi}{5}

  5. y=cos⁡(2x)y = \cos(2x)

    Show answer

    π\pi