Precalculus · Sequences and series

Find the Sum of an Infinite Geometric Series

Problem

8+4+2+1+⋯8 + 4 + 2 + 1 + \cdots

Answer

1616

An infinite geometric series can add up to a finite number when each term is smaller than the last. The formula S = a / (1 - r) does the work.

Step-by-step solution

  1. Find the first term and the common ratio.

    a=8,r=48=12a = 8,\quad r = \frac{4}{8} = \frac{1}{2}

    Why: Each term is half of the one before it, so the ratio is 1/2.

  2. Check that the series converges.

    ∣r∣=12<1|r| = \frac{1}{2} < 1

    Why: An infinite geometric series has a finite sum only when the ratio is between -1 and 1.

  3. Use the sum formula.

    S=a1−r=81−1/2=81/2=16S = \frac{a}{1 - r} = \frac{8}{1 - 1/2} = \frac{8}{1/2} = 16

    Why: Dividing by 1/2 is the same as multiplying by 2.

Common mistakes

  • Using the finite sum formula with r^n. The infinite series has no n.
  • Mixing up the numerator and denominator of the formula.
  • Using the formula when the ratio is 2 or larger. Then the sum grows without bound.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. 1+12+14+⋯1 + \frac{1}{2} + \frac{1}{4} + \cdots

    Show answer

    22

  2. 6+3+32+⋯6 + 3 + \frac{3}{2} + \cdots

    Show answer

    1212

  3. 9+3+1+⋯9 + 3 + 1 + \cdots

    Show answer

    272\frac{27}{2}

  4. 4+2+1+⋯4 + 2 + 1 + \cdots

    Show answer

    88

  5. 2+12+18+⋯2 + \frac{1}{2} + \frac{1}{8} + \cdots

    Show answer

    83\frac{8}{3}