Precalculus · Sequences and series

How to Find the Sum of a Geometric Series

Problem

2+6+18+54+1622 + 6 + 18 + 54 + 162

Answer

242242

A geometric series multiplies by the same number at every step. When the number of terms is small you can add by hand, but the formula always works.

Step-by-step solution

  1. Find the common ratio.

    r=62=3r = \frac{6}{2} = 3

    Why: Each term is multiplied by the same number.

  2. Count the terms.

    a=2,r=3,n=5a = 2,\quad r = 3,\quad n = 5

    Why: The formula needs the first term, the ratio and the number of terms.

  3. Write the sum formula.

    S=a(rn−1)r−1S = \frac{a(r^n - 1)}{r - 1}

    Why: The formula adds the first n terms of a geometric series.

  4. Substitute and calculate.

    S=2(35−1)3−1=2(242)2=242S = \frac{2(3^5 - 1)}{3 - 1} = \frac{2(242)}{2} = 242

    Why: 3 to the fifth power is 243, and 243 minus 1 is 242.

Common mistakes

  • Using r = 3 in the denominator as r + 1.
  • Raising 3 to the fourth power instead of the fifth. Use n, not n - 1.
  • Adding the terms by hand and making an arithmetic slip.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. 1+2+4+81 + 2 + 4 + 8

    Show answer

    1515

  2. 3+9+273 + 9 + 27

    Show answer

    3939

  3. 1+3+9+27+811 + 3 + 9 + 27 + 81

    Show answer

    121121

  4. 2+4+82 + 4 + 8

    Show answer

    1414

  5. 5+10+20+405 + 10 + 20 + 40

    Show answer

    7575