Precalculus · Logarithms and exponentials

How to Evaluate a Logarithm

Problem

log⁡232\log_2 32

Answer

55

A logarithm is an exponent in disguise. The statement log base b of x equals y means the same as b to the power y equals x.

Step-by-step solution

  1. Turn the logarithm into a power question.

    2y=322^y = 32

    Why: A logarithm asks: to what power do I raise the base?

  2. Write 32 as a power of 2.

    32=2532 = 2^5

    Why: 2 times 2 times 2 times 2 times 2 is 32.

  3. Match the exponents.

    2y=25⇒y=52^y = 2^5 \Rightarrow y = 5

    Why: Equal powers with the same base have equal exponents.

Common mistakes

  • Answering 32. The logarithm is the exponent, not the number.
  • Swapping the base and the answer. The base stays 2.
  • Using base 10 out of habit. Read the small number.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. log⁡216\log_2 16

    Show answer

    44

  2. log⁡327\log_3 27

    Show answer

    33

  3. log⁡101000\log_{10} 1000

    Show answer

    33

  4. log⁡5125\log_5 125

    Show answer

    33

  5. log⁡21\log_2 1

    Show answer

    00