Algebra 2 · Rational exponents and radicals

How to Solve a Radical Equation

Problem

x+5=4\sqrt{x + 5} = 4

Answer

x=11x = 11

A radical equation has the variable inside a square root. Square both sides to remove the root, then solve the small equation that remains.

Step-by-step solution

  1. Square both sides.

    (x+5)2=42\left(\sqrt{x + 5}\right)^2 = 4^2

    Why: Squaring undoes the square root.

  2. Simplify both sides.

    x+5=16x + 5 = 16

    Why: The left side becomes x + 5 and the right side becomes 16.

  3. Subtract 5 from both sides.

    x=11x = 11

    Why: Subtracting undoes the addition.

  4. Check the answer in the original equation.

    11+5=16=4\sqrt{11 + 5} = \sqrt{16} = 4

    Why: Squaring can create false solutions, so every answer needs a check.

Common mistakes

  • Squaring each term separately. Square the whole side.
  • Skipping the check. Some equations give an extra value that fails.
  • Subtracting 5 before squaring. Remove the root first.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. x+2=3\sqrt{x + 2} = 3

    Show answer

    x=7x = 7

  2. x−4=5\sqrt{x - 4} = 5

    Show answer

    x=29x = 29

  3. 2x+1=5\sqrt{2x + 1} = 5

    Show answer

    x=12x = 12

  4. x=9\sqrt{x} = 9

    Show answer

    x=81x = 81

  5. 3x−2=4\sqrt{3x - 2} = 4

    Show answer

    x=6x = 6