Calculus · Limits

How to Evaluate a Limit by Substitution

Problem

lim⁡x→2(x2+3x)\lim_{x \to 2} \left(x^2 + 3x\right)

Answer

1010

Direct substitution is the first test for any limit. It works whenever the expression is continuous at the point, which covers every polynomial.

Step-by-step solution

  1. Substitute x = 2 into the expression.

    22+3(2)2^2 + 3(2)

    Why: Polynomials are continuous everywhere, so the limit equals the function value.

  2. Simplify the expression.

    4+64 + 6

    Why: Evaluate the power first, then the product.

  3. Write the limit.

    4+6=104 + 6 = 10

    Why: The expression approaches 10 as x approaches 2.

Common mistakes

  • Refusing to substitute because the expression looks complicated. Try substitution first every time.
  • Substituting before simplifying the power and product in the right order.
  • Reporting the derivative or the slope instead of the limit value.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. lim⁡x→3(x2−1)\lim_{x \to 3} \left(x^2 - 1\right)

    Show answer

    88

  2. lim⁡x→1(2x+5)\lim_{x \to 1} \left(2x + 5\right)

    Show answer

    77

  3. lim⁡x→2(x3−2)\lim_{x \to 2} \left(x^3 - 2\right)

    Show answer

    66

  4. lim⁡x→3x+1x−1\lim_{x \to 3} \frac{x + 1}{x - 1}

    Show answer

    22

  5. lim⁡x→4(5x−3)\lim_{x \to 4} \left(5x - 3\right)

    Show answer

    1717