Algebra 2 · Factoring polynomials

How to Factor x^2 + bx + c

Problem

x2+7x+12x^2 + 7x + 12

Answer

(x+3)(x+4)(x + 3)(x + 4)

To factor x squared plus bx plus c, find two numbers that multiply to c and add to b. Their signs follow from the signs of b and c.

Step-by-step solution

  1. List number pairs that multiply to 12.

    1⋅12,2⋅6,3⋅41 \cdot 12,\quad 2 \cdot 6,\quad 3 \cdot 4

    Why: The constant term 12 comes from multiplying the two numbers in the brackets.

  2. Find the pair that adds to 7.

    3+4=73 + 4 = 7

    Why: The middle coefficient 7 is the sum of the two numbers.

  3. Write the factored form with the pair.

    (x+3)(x+4)(x + 3)(x + 4)

    Why: Both signs are plus because 12 and 7 are both positive.

  4. Check by expanding.

    (x+3)(x+4)=x2+7x+12(x + 3)(x + 4) = x^2 + 7x + 12

    Why: Expanding returns the original trinomial.

Common mistakes

  • Using -3 and -4. That pair multiplies to 12 but adds to -7.
  • Swapping the sum and the product rules.
  • Writing only one bracket. A factored trinomial is a product of two brackets.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. x2+5x+6x^2 + 5x + 6

    Show answer

    (x+2)(x+3)(x + 2)(x + 3)

  2. x2−x−6x^2 - x - 6

    Show answer

    (x−3)(x+2)(x - 3)(x + 2)

  3. x2−9x+20x^2 - 9x + 20

    Show answer

    (x−4)(x−5)(x - 4)(x - 5)

  4. x2+2x−15x^2 + 2x - 15

    Show answer

    (x+5)(x−3)(x + 5)(x - 3)

  5. x2−11x+24x^2 - 11x + 24

    Show answer

    (x−3)(x−8)(x - 3)(x - 8)