Precalculus · Functions and domains

How to Find the Domain of a Fraction Function

Problem

f(x)=1x+5f(x) = \frac{1}{x + 5}

Answer

x≠−5x \neq -5

A fraction is undefined wherever its denominator is zero. To find the domain, solve denominator equals zero and remove those values from the real numbers.

Step-by-step solution

  1. Write the rule for a fraction.

    denominator≠0\text{denominator} \neq 0

    Why: Division by zero is undefined, so the denominator cannot be zero.

  2. Set the denominator equal to zero to find the forbidden input.

    x+5=0⇒x=−5x + 5 = 0 \Rightarrow x = -5

    Why: This is the single value that makes the function undefined.

  3. Write the domain as every other real number.

    x≠−5x \neq -5

    Why: All other inputs give a real output.

Common mistakes

  • Setting the numerator equal to zero. Only the denominator causes division by zero.
  • Writing x > -5 or another inequality. A single excluded value leaves the rest of the line open on both sides.
  • Including x = -5 in the domain.

Practice problems

Use the same method. Work each problem on paper, then open the answer to check.

  1. f(x)=1x−6f(x) = \frac{1}{x - 6}

    Show answer

    x≠6x \neq 6

  2. f(x)=12x+4f(x) = \frac{1}{2x + 4}

    Show answer

    x≠−2x \neq -2

  3. f(x)=xx−9f(x) = \frac{x}{x - 9}

    Show answer

    x≠9x \neq 9

  4. f(x)=1x2−16f(x) = \frac{1}{x^2 - 16}

    Show answer

    x≠4, x≠−4x \neq 4,\ x \neq -4

  5. f(x)=17−xf(x) = \frac{1}{7 - x}

    Show answer

    x≠7x \neq 7